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Puzzle 1 A _ _ _ 5 4 _ _ B C D _ _ _ 2 6 _ _ _ E 7 _ _ _ _ F 5 _ G _ _ _ 8 _ H 1 _ I _ 9 |
Puzzle 2 A _ 6 B _ _ _ 4 C _ _ _ _ 7 1 _ D _ 7 1 _ _ _ _ E 9 _ F G _ _ 8 2 _ _ H 5 _ _ _ I |
Source: Original. [Has anyone seen this sort of puzzle before? It seems new to me.]
Puzzle 1: C A D B H I F G E 4 7 8 1 6 5 2 9 3 or 4 6 8 7 1 5 2 3 9 C A D B H E I G F Puzzle 2: G C F B D I A E H 9 5 1 8 3 2 7 4 6
Logic for puzzle 1
From A---5 and 5-G- we have A---5-G-
G is at spot 7 or 8.
The first 2 spots must be A,C,or D and the last 2 are 2,3,or 9
1-I-9 has 5 possibilities:
1. | 1 | A | I | | 9 | 5 | | G | |
F has 2 possibilities:
1a.| 1 | A7 | I | | 9 | 5 | F | G | |
leaves no spot for E
1b.| 1 | A | I | 7 | 9 | 5 | | G | F |
forces H
| 1 | A | I8 | 7 | H9 | 5 | | G | F |
forces E
| 1 | A6 | I8 | 7 | H9 | E5 | | G | F |
leaves no spot for B.
2. | A | 1 | | I | 5 | 9 | | G | |
2 and 3 must be at the last 2 spots, forcing
| A | 1 | | I | D5 | 9 | | G3 | 2 |
forces E
| A | 1 | 6 | I | D5 | 9 | E | G3 | 2 |
leaves no space for B
Since I is not at spots 3 or 4 this means that the last 5 spots are
E,F,G,H, and I
This forces B to spot 4.
| 4 | | | B | | | | | |
D cannot be at spots 4 or 5, so 2 is not at spot 8 or 9, making the last
2 spots 3 and 9, thus eliminating case 3.
4. | 4 | | | B1 | | I | | 9 | 3 |
F&G can only be in the 7th and 8 spots, forcing E and then H
| 4 | | 8 | B1 | H6 | I | | 9 | E3 |
forces A---5-G-
| 4 | A | 8 | B1 | H6 | I5 | | G9 | E3 |
giving a solution
| C4 | A7 | D8 | B1 | H6 | I5 | F2 | G9 | E3 |
5. | 4 | | | B | 1 | | I | 3 | 9 |
forces A---5--G
| 4 | A | | B | 1 | 5 | I | G3 | 9 |
forces D,E,F and gives the solution
| C4 | A6 | D8 | B7 | H1 | E5 | I2 | G3 | F9 |
Puzzle 2
A _ 6
B _ _ _ 4
C _ _ _ _ 7
1 _ D _ 7
1 _ _ _ _ E
9 _ F
G _ _ 8
2 _ _ H
5 _ _ _ I
Note the the first two must be A,B,C, or G
The C-E hints give us
| C | 1 | | D | | 7 | E |
Which can fit in 3 ways
1.| | | C | 1 | | D | | 7 | E |
Then G| | |8 can fit in 2 places.
1a. | | G | C | 1 | 8 | D | | 7 | E |
This forces B into
| | G | C | 1 | B8 | D | | 7 | E4 |
and A must be on the left
| A | G | C6 | 1 | B8 | D | | 7 | E4 |
leaving no place for I.
1b. | | | C | 1G | | D | 8 | 7 | E |
Then A&B must be on the left,
| A | B | C6 | 1G | | D4 | 8 | 7 | E |
forces F
| A | B | C6 | 1G | 9 | D4 | F8 | 7 | E |
leaves no space for H&I
2. | C | 1 | | D | | 7 | E | | |
b---4 fits in 2 ways, and the 2nd spot is either A or G
2a. | C | G1 | B | D | 8 | 7 | E4 | | |
forces A&H into the same square
2b. | C | A1 | B | D6 | | 7 | E4 | | |
forces F and forces the last square to be I
| C | A1 | B9 | D6 | F5 | 7 | E4 | | I |
forces G&H into the same square
2c. | C | A1 | | D6 | B | 7 | E | | 4 |
leaves no square for G
2d. | C | G1 | | D | B8 | 7 | E | | 4 |
The 3rd and last squares cannot be A, H, or I forcing
F into both squares
3. | | C | 1 | | D | | 7 | E | |
b---4 fits in 2 ways
3a. | B | C | 1 | | D4 | | 7 | E | |
forces the last square to be H
| B | C | 1 | | D4 | 2 | 7 | E | H |
forces G
| B | C | 1 | | D4 | G2 | 7 | E | H8 |
leaving no space for A
3b. | | C | 1 | B | D | | 7 | E4 | |
forces the first square to be G
| G | C | 1 | B8 | D | | 7 | E4 | |
forces H
| G | C | 1 | B8 | D | 2 | 7 | E4 | H |
forces I
| G | C5 | 1 | B8 | D | I2 | 7 | E4 | H |
yielding the solution
| G9 | C5 | 1F | B8 | D3 | I2 | A7 | E4 | H6 |