Puzzle 1 A _ _ _ 5 4 _ _ B C D _ _ _ 2 6 _ _ _ E 7 _ _ _ _ F 5 _ G _ _ _ 8 _ H 1 _ I _ 9 |
Puzzle 2 A _ 6 B _ _ _ 4 C _ _ _ _ 7 1 _ D _ 7 1 _ _ _ _ E 9 _ F G _ _ 8 2 _ _ H 5 _ _ _ I |
Source: Original. [Has anyone seen this sort of puzzle before? It seems new to me.]
Puzzle 1: C A D B H I F G E 4 7 8 1 6 5 2 9 3 or 4 6 8 7 1 5 2 3 9 C A D B H E I G F Puzzle 2: G C F B D I A E H 9 5 1 8 3 2 7 4 6
Logic for puzzle 1 From A---5 and 5-G- we have A---5-G- G is at spot 7 or 8. The first 2 spots must be A,C,or D and the last 2 are 2,3,or 9 1-I-9 has 5 possibilities: 1. | 1 | A | I | | 9 | 5 | | G | | F has 2 possibilities: 1a.| 1 | A7 | I | | 9 | 5 | F | G | | leaves no spot for E 1b.| 1 | A | I | 7 | 9 | 5 | | G | F | forces H | 1 | A | I8 | 7 | H9 | 5 | | G | F | forces E | 1 | A6 | I8 | 7 | H9 | E5 | | G | F | leaves no spot for B. 2. | A | 1 | | I | 5 | 9 | | G | | 2 and 3 must be at the last 2 spots, forcing | A | 1 | | I | D5 | 9 | | G3 | 2 | forces E | A | 1 | 6 | I | D5 | 9 | E | G3 | 2 | leaves no space for B Since I is not at spots 3 or 4 this means that the last 5 spots are E,F,G,H, and I This forces B to spot 4. | 4 | | | B | | | | | | D cannot be at spots 4 or 5, so 2 is not at spot 8 or 9, making the last 2 spots 3 and 9, thus eliminating case 3. 4. | 4 | | | B1 | | I | | 9 | 3 | F&G can only be in the 7th and 8 spots, forcing E and then H | 4 | | 8 | B1 | H6 | I | | 9 | E3 | forces A---5-G- | 4 | A | 8 | B1 | H6 | I5 | | G9 | E3 | giving a solution | C4 | A7 | D8 | B1 | H6 | I5 | F2 | G9 | E3 | 5. | 4 | | | B | 1 | | I | 3 | 9 | forces A---5--G | 4 | A | | B | 1 | 5 | I | G3 | 9 | forces D,E,F and gives the solution | C4 | A6 | D8 | B7 | H1 | E5 | I2 | G3 | F9 |
Puzzle 2 A _ 6 B _ _ _ 4 C _ _ _ _ 7 1 _ D _ 7 1 _ _ _ _ E 9 _ F G _ _ 8 2 _ _ H 5 _ _ _ I Note the the first two must be A,B,C, or G The C-E hints give us | C | 1 | | D | | 7 | E | Which can fit in 3 ways 1.| | | C | 1 | | D | | 7 | E | Then G| | |8 can fit in 2 places. 1a. | | G | C | 1 | 8 | D | | 7 | E | This forces B into | | G | C | 1 | B8 | D | | 7 | E4 | and A must be on the left | A | G | C6 | 1 | B8 | D | | 7 | E4 | leaving no place for I. 1b. | | | C | 1G | | D | 8 | 7 | E | Then A&B must be on the left, | A | B | C6 | 1G | | D4 | 8 | 7 | E | forces F | A | B | C6 | 1G | 9 | D4 | F8 | 7 | E | leaves no space for H&I 2. | C | 1 | | D | | 7 | E | | | b---4 fits in 2 ways, and the 2nd spot is either A or G 2a. | C | G1 | B | D | 8 | 7 | E4 | | | forces A&H into the same square 2b. | C | A1 | B | D6 | | 7 | E4 | | | forces F and forces the last square to be I | C | A1 | B9 | D6 | F5 | 7 | E4 | | I | forces G&H into the same square 2c. | C | A1 | | D6 | B | 7 | E | | 4 | leaves no square for G 2d. | C | G1 | | D | B8 | 7 | E | | 4 | The 3rd and last squares cannot be A, H, or I forcing F into both squares 3. | | C | 1 | | D | | 7 | E | | b---4 fits in 2 ways 3a. | B | C | 1 | | D4 | | 7 | E | | forces the last square to be H | B | C | 1 | | D4 | 2 | 7 | E | H | forces G | B | C | 1 | | D4 | G2 | 7 | E | H8 | leaving no space for A 3b. | | C | 1 | B | D | | 7 | E4 | | forces the first square to be G | G | C | 1 | B8 | D | | 7 | E4 | | forces H | G | C | 1 | B8 | D | 2 | 7 | E4 | H | forces I | G | C5 | 1 | B8 | D | I2 | 7 | E4 | H | yielding the solution | G9 | C5 | 1F | B8 | D3 | I2 | A7 | E4 | H6 |