Source: Reader Rich Polster.
I know nothing of the art of playing Blackjack or betting, but I suppose that in this game each is being dealt two cards and that "17 to 1" means that in case you win, your net gain is 17 dollar, rather then 16 dollar for each dollar you bet. 1. Probability of getting a Blackjack = 16/52 * 4/51 * 2 = 32/663 2. Probability of two hands BOTH getting Blackjack = 16/52 * 4/51 * 2 * 15/50 * 3/49 * 2 = 11520/6497400 = 96/54145 3. This is easier calculated with the rule of the complement: we first calculate the probability that there is exactly one Blackjack. your hand dealers hand first second first second Ace 10-King Ace rest 4/52 * 16/51 * 2 * 3/50 * 32/49 * 2 Ace 10-King Ace Ace 4/52 * 16/51 * 2 * 3/50 * 2/49 Ace 10-King 10-King rest 4/52 * 16/51 * 2 * 15/50 * 32/49 * 2 Ace 10-King 10-King 10-King 4/52 * 16/51 * 2 * 15/50 * 14/49 Ace 10-King rest rest 4/52 * 16/51 * 2 * 32/50 * 31/49 Adding up gives the probability that you get a Blackjack and the dealer has no Blackjack : 302080/6497400 = 7552/162435 The probability that there is exactly ONE Blackjack is double this number: 604160/6497400 = 15104/162435 So the probability that neither has a Blackjack is 1 - (11520+604160)/6497400 = 5881720/6497400 = 11311/12495. Expected profit(loss) if you bet a dollar on each hand: 40 * 96/54145 + 16 * 15104/162435 - 2 * 11311/12495 = -0.251805 dollar Expected profit(loss) if you bet a dollar on your own hand: 17 * 32/663 - 1 * 631/663 = -0.131222 dollar. What odds would give a fair game? Betting on your own hand with odds x-to-1 gives x * 32/663 - 1 * 631/663 = 0. Solving gives odds 19.7-to-1 (or the be precise 19.71875-to-1) Betting on both hands: suppose two Blackjacks pays y-to-1 and one Blackjack pays x-to-1. We get the equation: 2y * 11520/6497400 + (x-1) * 604160/6497400 - 2 * 5881720/6497400 = 0 This can be reduced to the equation 288 * y + 7552 * x = 154595 There are several solutions (x,y) i.e. (x,y) = (19.71875 , 19.71875) or (x,y) = (18 , 64.79) or (x,y) = (19 , 38.56)) or (x,y) = (19.5 , 25.45).