Like the earlier problems,
Domino Magic Square and More Dominoes, this problem
asks you to create a magic square. From a regular set of dominoes,
remove all blanks, 5's and 6's, leaving 1-1, 1-2, ..., 4-4, 10
dominoes in all. Remove two dominoes of your choice and arrange
the remaining 8 dominoes in a 4x4 grid, such
that the sum of the dots in each row, column, and major
diagonal is the same.
Which dominoes can be removed?
Solution received from
The pair set aside must have a number of spots X such that the
quantity 50-X is divisible by four.
A Sum=10 solution, setting aside the 2-2 and the 3-3, and a Sum=9
solution, setting aside the 3-3 and 4-4. A Sum=11 solution can
be found by substituting (5-i) for every (i) in the Sum=9.
I know more exist. Anyone care to add to the solutions?
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