Like the earlier problems,
Domino Magic Square and More Dominoes, this problem
asks you to create a magic square. From a regular set of dominoes,
remove all blanks, 5's and 6's, leaving 1-1, 1-2, ..., 4-4, 10
dominoes in all. Remove two dominoes of your choice and arrange
the remaining 8 dominoes in a 4x4 grid, such
that the sum of the dots in each row, column, and major
diagonal is the same.
Which dominoes can be removed?
Source:
Original
Solution received from
Jon Abraham:
The pair set aside must have a number of spots X such that the
quantity 50-X is divisible by four.
A Sum=10 solution, setting aside the 2-2 and the 3-3, and a Sum=9
solution, setting aside the 3-3 and 4-4. A Sum=11 solution can
be found by substituting (5-i) for every (i) in the Sum=9.
4-1 3-2
1-1 4-4
3-4 2-1
2-4 1-3
2-2 2-3
1-2 2-4
3-1 4-1
3-4 1-1
I know more exist. Anyone care to add to the solutions?
Mail to Ken