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ONE + TWO + FOUR = SEVEN

In the equation above, each letter represents a digit. Determine the value
for each letter.
*
(If ambiguity exists, let later letters , i.e. "W", be greater than earlier
letters, i.e. "U".)
*

Source:
Original.

Solutions were received from
Arturo Pascalin,
Bill Beall,
Philippe Fondanaiche,
Joseph W. DeVincentis,
Denis Borris,
Carlos Rivera,
Robert T McQuaid,
Alexander Doskey,
Radu Ionescu,
David Betanzos.
There are only 34 valid solutions, 8 if you don't consider leading zeros.
When we limit W>U, those 8 become these 4:
ONE + TWO + FOUR = SEVEN
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350 683 9372 10405...smallest "seven"
530 645 9528 10703
630 546 9627 10803...largest "seven"
940 739 8925 10604

Depending on the order of application of my "ambiguity rule" various
solutions can be singled out, so I just left them all in the list.
(For example, if F is to be smaller than O, then the last solution is best,
but if V is to be greater than most, then the third solution is best.)

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