- Find the dimensions of all rectangles that have area equal numerically to M times the perimeter, where both the length and the width are whole numbers. (M=1,2,3,4,5)
- Repeat for perimeter equal to M times the area.

Solutions were received from Stan Morrice, Alan Zimmermann, Henry Bottomley, Richard Winterstein, Ravi Subramanian, Kirk Bresniker, Robert Mattson, Joseph DeVincentis, Michael Moyer, Philippe Fondanaiche, and Sandy Thompson. Two representative solutions are included here.

From Al Zimmermann:

M=1: (4,4), (3,6) M=2: (8,8), (6,12), (5,20) M=3: (12,12), (10,15), (9,18), (8,24), (7,42) M=4: (16,16), (12,24), (10,40), (9,72) M=5: (20,20), (15,30), (14,35), (12,60), (11,110) Some of these rectangles are just "multiples" of smaller rectangles. Specifically, if M = Area(x,y) / Perimeter(x,y) then kM = Area(kx,ky) / Perimeter(kx,ky). I think such rectangles are inherently less interesting. The abbreviated list of rectangles which are not multiples of smaller ones (that is, where M, x, and y have no common divisor other than 1) is: M=1: (4,4), (3,6) M=2: (5,20) M=3: (10,15), (8,24), (7,42) M=4: (9,72) M=5: (14,35), (12,60), (11,110) Extending this list of "primitive" rectangles to M=10 yields: M=6: (21,28), (13,156) M=7: (18,63), (16,112), (15,210) M=8: (17,272) M=9: (22,99), (20,180), (19,342) M=10: (36,45), (21,420) The largest rectangle for a given M appears to always be (2M+1,4M^2+2M). [KD: Stan Morrice stated this as "the dimensions are X=2*M+1, and Y=2*M*X." I thought that was a nice compact statement.] (2M+2,2M^2+2M) and (2M+4,M^2+2M) also work, although neither is primitive if M is even. > Repeat for perimeter equal to M times the area. M=1: (4,4), (3,6) M=2: (2,2) M=3: (1,2) M=4: (1,1) M=5:From Ravi Subramanian:

Let the dimensions of the rectangle be a, b. Area = a * b Perimeter = 2 * (a + b) First part : Area = M * Perimeter a * b = M * 2 * (a + b) 1 / a + 1 / b = 1 / (2 * M) let (2 * M) = N 1 / a + 1 / b = 1 / N Let a <= b. Hence N < a <= 2 * N. Let a = (N + d) with 0 < d <= N So 1 / (N + d) + 1 / b = 1 / N so b = N * (N + d) / d => d is a factor N^2 => d is a product of 2 factors of N. So considering various M's M N d a b P A 1 2 1 3 6 18 18 2 4 4 16 16 2 4 1 5 20 50 100 2 6 12 36 72 4 8 8 32 64 3 6 1 7 42 98 294 2 8 24 64 192 3 9 18 54 162 4 10 15 50 150 6 12 12 48 144 4 8 1 9 72 162 648 2 10 40 100 400 4 12 24 72 288 8 16 16 64 256 5 10 1 11 110 242 1210 2 12 60 144 720 4 14 35 98 490 5 15 30 90 450 10 20 20 80 400 Second part : Perimeter = M * Area 2 * (a + b) = M * a * b 1 / a + 1 / b = M / 2 Let a <= b. So 1 / a >= M / 4 a <= 4 / M and a > 2 / M No solution for M >= 5! M a b A P 1 3 6 18 18 4 4 16 16 2 2 2 4 8 3 1 2 2 6 4 1 1 1 4

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